Optimal. Leaf size=138 \[ -\frac{2 (a+b x) (B d-A e)}{e \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (b d-a e)}-\frac{2 (a+b x) (A b-a B) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{\sqrt{b} \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^{3/2}} \]
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Rubi [A] time = 0.110026, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.114, Rules used = {770, 78, 63, 208} \[ -\frac{2 (a+b x) (B d-A e)}{e \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (b d-a e)}-\frac{2 (a+b x) (A b-a B) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{\sqrt{b} \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 770
Rule 78
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{A+B x}{(d+e x)^{3/2} \sqrt{a^2+2 a b x+b^2 x^2}} \, dx &=\frac{\left (a b+b^2 x\right ) \int \frac{A+B x}{\left (a b+b^2 x\right ) (d+e x)^{3/2}} \, dx}{\sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{2 (B d-A e) (a+b x)}{e (b d-a e) \sqrt{d+e x} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left ((A b-a B) \left (a b+b^2 x\right )\right ) \int \frac{1}{\left (a b+b^2 x\right ) \sqrt{d+e x}} \, dx}{(b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{2 (B d-A e) (a+b x)}{e (b d-a e) \sqrt{d+e x} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (2 (A b-a B) \left (a b+b^2 x\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a b-\frac{b^2 d}{e}+\frac{b^2 x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{e (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{2 (B d-A e) (a+b x)}{e (b d-a e) \sqrt{d+e x} \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 (A b-a B) (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{\sqrt{b} (b d-a e)^{3/2} \sqrt{a^2+2 a b x+b^2 x^2}}\\ \end{align*}
Mathematica [A] time = 0.0895556, size = 128, normalized size = 0.93 \[ \frac{2 (a+b x) \left (e \sqrt{d+e x} (a B-A b) \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )-\sqrt{b} (b d-a e) (B d-A e)\right )}{\sqrt{b} e \sqrt{(a+b x)^2} \sqrt{d+e x} (b d-a e)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.011, size = 148, normalized size = 1.1 \begin{align*} -2\,{\frac{bx+a}{\sqrt{ \left ( bx+a \right ) ^{2}}e \left ( ae-bd \right ) \sqrt{ \left ( ae-bd \right ) b}\sqrt{ex+d}} \left ( A\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) \sqrt{ex+d}be-B\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) \sqrt{ex+d}ae+A\sqrt{ \left ( ae-bd \right ) b}e-B\sqrt{ \left ( ae-bd \right ) b}d \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B x + A}{\sqrt{{\left (b x + a\right )}^{2}}{\left (e x + d\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.6475, size = 767, normalized size = 5.56 \begin{align*} \left [\frac{{\left ({\left (B a - A b\right )} e^{2} x +{\left (B a - A b\right )} d e\right )} \sqrt{b^{2} d - a b e} \log \left (\frac{b e x + 2 \, b d - a e + 2 \, \sqrt{b^{2} d - a b e} \sqrt{e x + d}}{b x + a}\right ) - 2 \,{\left (B b^{2} d^{2} + A a b e^{2} -{\left (B a b + A b^{2}\right )} d e\right )} \sqrt{e x + d}}{b^{3} d^{3} e - 2 \, a b^{2} d^{2} e^{2} + a^{2} b d e^{3} +{\left (b^{3} d^{2} e^{2} - 2 \, a b^{2} d e^{3} + a^{2} b e^{4}\right )} x}, -\frac{2 \,{\left ({\left ({\left (B a - A b\right )} e^{2} x +{\left (B a - A b\right )} d e\right )} \sqrt{-b^{2} d + a b e} \arctan \left (\frac{\sqrt{-b^{2} d + a b e} \sqrt{e x + d}}{b e x + b d}\right ) +{\left (B b^{2} d^{2} + A a b e^{2} -{\left (B a b + A b^{2}\right )} d e\right )} \sqrt{e x + d}\right )}}{b^{3} d^{3} e - 2 \, a b^{2} d^{2} e^{2} + a^{2} b d e^{3} +{\left (b^{3} d^{2} e^{2} - 2 \, a b^{2} d e^{3} + a^{2} b e^{4}\right )} x}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{A + B x}{\left (d + e x\right )^{\frac{3}{2}} \sqrt{\left (a + b x\right )^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16135, size = 158, normalized size = 1.14 \begin{align*} -\frac{2 \,{\left (B a \mathrm{sgn}\left (b x + a\right ) - A b \mathrm{sgn}\left (b x + a\right )\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{\sqrt{-b^{2} d + a b e}{\left (b d - a e\right )}} - \frac{2 \,{\left (B d \mathrm{sgn}\left (b x + a\right ) - A e \mathrm{sgn}\left (b x + a\right )\right )}}{{\left (b d e - a e^{2}\right )} \sqrt{x e + d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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